Physics - Unit & Dimension Question with Solution | TestHub

Dimensions of $\mu =[$ MLT ${}^{-2}{\mathrm{A}}^{-2}]$ Dimensions of $\in =\left[{\mathrm{M}}^{-1}{\mathrm{L}}^{-3}{\mathrm{T}}^4{\mathrm{A}}^2\right]$ Dimensions of $\mathrm{R}=\left[{\mathrm{ML}}^2{\mathrm{T}}^{-3}{\mathrm{A}}^{-2}\right]$ $$\begin{array}{rl}& \therefore \frac{\text{ Dimensions of }\mu }{\text{ Dimensions of }e}=\frac{\left[{\mathrm{MLT}}^{-2}{\mathrm{A}}^{-2}\right]}{\left[{\mathrm{M}}^{-1}{\mathrm{L}}^{-3}{\mathrm{T}}^4{\mathrm{A}}^2\right]}\\ & =\left[{\mathrm{M}}^2{\mathrm{L}}^4{\mathrm{T}}^{-6}{\mathrm{A}}^{-4}\right]=\left[{\mathrm{R}}^2\right]\end{array}$$