Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

If the error in the measurement of momentum is $20 %$ , then the error in the calculation of kinetic energy is (assume the error in measurement of $m$ as zero)

Options:

Answer:

Solution:

$KE = \frac{1}{2} \frac{p^{2}}{m}$

${KE}_{1} = \frac{1}{2} \frac{p^{2}}{m}$

$p_{1} = \frac{6}{5} p$

${KE}_{2} = \frac{1}{2} (\frac{36}{25}) \frac{p^{2}}{m}$

$ΔKE = {KE}_{2} - {KE}_{1}$

$= \frac{1}{2} [\frac{{(\frac{6}{5} p)}^{2} - p^{2}}{m}]$

$= \frac{11}{25} \frac{p^{2}}{m}$

Percentage change in kinetic energy $= \frac{ΔKE}{{KE}_{1}} \times 100$

$= \frac{11}{25} \times 100 = 44 %$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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