Physics - Unit & Dimension Question with Solution | TestHub

$\text{F}=\frac{1}{4\pi {\epsilon }_0}\frac{{\text{q}}_1{\text{q}}_2}{{\text{R}}^2}$

${\epsilon }_0=\frac{{\text{q}}_1{\text{q}}_2}{4\pi {\text{FR}}^2}$

Hence,${\epsilon }_0=\frac{{\text{C}}^2}{{\text{N . m}}^2}=\frac{{\left[\text{AT}\right]}^2}{\text{ML}{\text{T}}^{-2}{\text{. L}}^2}=\left[{\text{M}}^{-1}{\text{ L}}^{-3}{\text{ T}}^4{\text{ A}}^2\right]$