Physics - Unit & Dimension Question with Solution | TestHub

The dimension of$y=\frac{e^2}{4\mathrm{\pi }{\mathrm{\epsilon }}_{0}hc}$

Putting the dimensions of

$\left[e\right]=\left[Q\right]=\left[\mathrm{A}\mathrm{T}\right]$

$\left[{\mathrm{\epsilon }}_0\right]=\left[{\mathrm{M}}^{-1}{\mathrm{L}}^{-3}{\mathrm{T}}^4{\mathrm{A}}^2\right], h=\left[\mathrm{M}{\mathrm{L}}^2{\mathrm{T}}^{-1}\right], c=\left[\mathrm{L}{\mathrm{T}}^{-1}\right]$

$y=\frac{\left[{\mathrm{A}}^2{\mathrm{T}}^2\right]}{\left[{\mathrm{M}}^{-1}{\mathrm{L}}^{-3}{\mathrm{T}}^4{\mathrm{A}}^2\right]\left[\mathrm{M}{\mathrm{L}}^2{\mathrm{T}}^{-1}\right]\left[\mathrm{L}{\mathrm{T}}^{-1}\right]}$

$y=\left[{\mathrm{M}}^0{\mathrm{L}}^0{\mathrm{T}}^0\right]$