Select the dimensional formula of B 2 2 μ 0

B 2 2 μ 0 = E n e r g y d e n s i t y = E n e r g y V o l u m e ⇒ ML 2 T - 2 L 3 = ML - 1 T - 2

Start Free Mock LoginAlready registered? Login here

Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

Select the dimensional formula of $\frac{B^{2}}{2 μ_{0}}$

Options:

Answer:

Solution:

$\frac{B^{2}}{2 μ_{0}} = E n e r g y d e n s i t y = \frac{E n e r g y}{V o l u m e}$

$\Rightarrow \frac{[{ML}^{2} T^{- 2}]}{[L^{3}]} = [{ML}^{- 1} T^{- 2}]$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...