The resistance R = V I , where V = ( 100 ± 5 ) V and I = 10 ± 0.2 A . The maximum percentage error in R is

Given, V = 100 ± 5 V ⇒ ∆ V = 5 V I = 10 ± 0.2 A ⇒ ∆ I = 0.2 A R = V I ∆ R R = ∆ V V + ∆ I I = 5 100 + 0.2 10 = 0.05 + 0.02 = 0.07 = 7 %

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Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

The resistance $R = \frac{V}{I}$ , where $V = (100 \pm 5) V$ and $I = (10 \pm 0.2) A$ . The maximum percentage error in $R$ is

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Answer:

Solution:

Given, $V = (100 \pm 5) V \Rightarrow ∆ V = 5 V$

$I = (10 \pm 0.2) A \Rightarrow ∆ I = 0.2 A$

$R = \frac{V}{I}$

$\frac{∆ R}{R} = \frac{∆ V}{V} + \frac{∆ I}{I}$

$= \frac{5}{100} + \frac{0.2}{10} = 0.05 + 0.02$

$= 0.07$

$= 7 %$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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