The voltage and current in a conductor are measured as ( 50 ± 2 ) V and ( 5 ± 0 .2 ) A . The percentage error in the calculation of resistance is

R = V I Δ R R = Δ V V + Δ I I ∴ % e r r o r i n R = 2 50 × 100 + 0.2 5 × 100 = 8 %

Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

The voltage and current in a conductor are measured as $(50 \pm 2) V$ and $(5 \pm 0 .2) A$ . The percentage error in the calculation of resistance is

Answer:

Solution:

$R = \frac{V}{I}$

$\frac{Δ R}{R} = \frac{Δ V}{V} + \frac{Δ I}{I}$

$∴ % e r r o r i n R = \frac{2}{50} \times 100 + \frac{0.2}{5} \times 100 = 8 %$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

Loading discussions...