Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

If $v = \frac{A}{t} + B t^{2} + C t^{3}$ where $v$ is velocity, $t$ is time and $A, B$ and $C$ are constants, then the dimensional formula of $B$ is

Options:

Answer:

Solution:

Dimension of velocity = $[M^{0} L^{1} T^{- 1}]$

$[v] = [B t^{2}]$

$∴ [B] = \frac{[v]}{[t^{2}]} = \frac{[M^{0} L^{1} T^{- 1}]}{[T^{2}]} = [L^{1} T^{- 3}]$

Stream:NTA_ABHYASSubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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