Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

Time $(T)$ , velocity $(C)$ and angular momentum $(h)$ are chosen as fundamental quantities instead of mass, length and time. In terms of these, the dimensions of mass would be:

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Answer:

Solution:

$M \propto T^{x} C^{y} h^{z}$
$M^{1} L^{0} T^{0} = {(T^{1})}^{x} {(L^{1} T^{- 1})}^{y} {(M^{1} L^{2} T^{- 1})}^{z}$
$[M^{1} L^{0} T^{0]} =[M^{z} L^{y + 2 z} T^{x - y - z}$ ]

$⟹ z = 1$
$y + 2 z = 0, x - y - z = 0$
$solving$
$y = - 2$
$and x = - 1$
$M \Rightarrow [T^{- 1} C^{- 2} h^{1}]$

Stream:NTA_ABHYASSubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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