Physics - Unit & Dimension Question with Solution | TestHub

As we know$c=\frac{1}{\sqrt{{\mu }_0{\epsilon }_0}}$
$\therefore \sqrt{\frac{{\epsilon }_0}{{\mu }_0}}=\sqrt{\frac{{\epsilon }_0^2}{{\mu }_0{\epsilon }_0}}={\epsilon }_{0}c$
$\therefore \left[\sqrt{\frac{{\epsilon }_0}{{\mu }_0}}\right]=\left[{\epsilon }_0\right]\left[c\right]=\left[{\text{M}}^{-1}{\text{L}}^{-3}{\text{T}}^4{\text{A}}^2\right]\left[{\text{LT}}^{-1}\right]$
${=\mathrm{M}}^{-1}{\mathrm{L}}^{-2}{\mathrm{T}}^3{\mathrm{A}}^2$