If force F is related with distance x and time t as F = A x + B t 2 , the dimensions of A B is

All terms of an equation must have same dimensions M L T – 2 = A L 1 2 = B T 2 A = M L T - 2 L B = M L T - 2 T 2

Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

If force $F$ is related with distance $x$ and time $t$ as $F = A \sqrt{x} + B t^{2}$ , the dimensions of $\frac{A}{B}$ is

Options:

Answer:

Solution:

All terms of an equation must have same dimensions

$[{M L T}^{- 2}] = [A L \frac{1}{2}] = [{B T}^{2}]$

$[A] = \frac{M L T^{- 2}}{\sqrt{L}}$

$[B] = \frac{M L T^{- 2}}{T^{2}}$

Stream:NTA_ABHYASSubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...