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PhysicsUnit & DimensionMiscellaneousEasy2 minPYQ_2020
PhysicsEasysingle choice

If speedV, areaAand forceFare chosen as fundamental units, then the dimension of Young's modulus will be :

Options:

Answer:
D
Solution:

YFaVbAc  Y=FA

MLT-2L2M1L1T-2aL1T-1bL2c

M1L-1T-2MaLa+b+2cT-2a-b

a + b + 2c = 1

2a + b = 2

a = 1, b = 0, c = 1

Y=F1V0A-1

Stream:JEESubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous
2mℹ️ Source: PYQ_2020

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