The radius of the earth and the radius of orbit around the sun are 6371 k m and 149 × 10 6 k m respectively. The order of magnitude of the diameter of the orbit is greater than that of earth by

D = 1.2752 × 10 4 r = 1.49 × 10 8 Order of D = 4 Order of r = 8 Difference = 8 - 4 = 4

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Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousMedium2 minPYQ_2019

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The radius of the earth and the radius of orbit around the sun are $6371 k m$ and $149 \times 10^{6} k m$ respectively. The order of magnitude of the diameter of the orbit is greater than that of earth by

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Answer:

Solution:

$D = 1.2752 \times 10^{4}$
$r = 1.49 \times 10^{8}$
Order of $D = 4$
Order of $r = 8$
Difference $= 8 - 4 = 4$

Stream:MHT_CETSubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2019

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