The force ‘F’ acting on a body of density ‘d’ are related by the reflection F = y d . The dimensions of ‘y’ are

The dimension of force F = M L T - 2 And density d = M L - 3 T 0 From the given relation, F = y d ⇒ y = F d Substituting the above dimensions, we get y = F d 1 / 2 = M L T - 2 M L - 3 T 0 1 / 2 = M 3 / 2 L - 1 2 T - 2

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Physics - Unit & Dimension Question with Solution | TestHub

PhysicsUnit & DimensionMiscellaneousHard2 minPYQ_2019

PhysicsHardsingle choice

The force ‘F’ acting on a body of density ‘d’ are related by the reflection $F = \frac{y}{\sqrt{d}}$ . The dimensions of ‘y’ are

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Answer:

Solution:

The dimension of force $[F] = [M L T^{- 2}]$
And density $[d] = [M L^{- 3} T^{0}]$
From the given relation, F $= \frac{y}{\sqrt{d}}$
$\Rightarrow y = F \sqrt{d}$
Substituting the above dimensions, we get
$[y] = [F] {[d]}^{1 / 2} = [M L T^{- 2}] {[M L^{- 3} T^{0}]}^{1 / 2}$
$= [M^{3 / 2} L^{- \frac{1}{2}} T^{- 2}]$

Stream:MHT_CETSubject:PhysicsTopic:Unit & DimensionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2019

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