Physics - Unit & Dimension Question with Solution | TestHub

Energy$U=\frac{1}{2}L{I}^2$

$\Rightarrow L=\frac{2U}{I^2}$

$\therefore \left[L\right]=\frac{\left[U\right]}{{\left[I\right]}^2}=\frac{\left[\mathrm{M}{\mathrm{L}}^2{\mathrm{T}}^{-2}\right]}{{\left[\mathrm{A}\right]}^2}=\left[\mathrm{M}{\mathrm{L}}^2{\mathrm{T}}^{-2}{\mathrm{A}}^{-2}\right]$