Physics - Unit & Dimension Question with Solution | TestHub

Dimension of torque is$\left[L^2{M}^1{T}^{-2}\right]$
Torque = Force$\times$Perpendicular distance
i.e.,$\tau =F\times r$
$\therefore$Dimension formula of$\tau =\left[ML{T}^{-2}\right]\left[L\right]$
$=\left[M{L}^2{T}^{-2}\right]$