Physics - Unit & Dimension Question with Solution | TestHub

Dimension of at = Dimension of F $[at]=[F]\Rightarrow [a]=\left[\frac{F}{t}\right]$ $[b]=\left[\frac{ML{T}^{-2}}{T}\right]\Rightarrow [a]=\left[ML{T}^{-3}\right]$ Dimension of ${\mathrm{bt}}^2=$ Dimension of $\mathrm{F}$ $\left[{\mathrm{bt}}^2\right]=[\mathrm{F}]\Rightarrow [\mathrm{b}]=\left[\frac{\mathrm{F}}{{\mathrm{t}}^2}\right]$ $[\mathrm{b}]=\left[\frac{\mathrm{ML}{\mathrm{T}}^{-4}}{{\mathrm{T}}^2}\right]\Rightarrow [\mathrm{b}]=\left[{\mathrm{MLT}}^{-4}\right]$