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Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveWavesMedium2 minQB

PhysicsMediumnumerical

Two open pipes of length 0.5 m have radii 1 cm and 2 cm. Using end correction $0.6 r$ at each end and $v = 340$ m/s, find the difference between their fundamental frequencies in Hz.

Answer:

7.60

Solution:

$f = v /2 (L + 1.2 r)$ . For 1 cm: $340/ (2 \times 0.512) = 332.0$ Hz. For 2 cm: $340/ (2 \times 0.524) = 324.4$ Hz. Difference $\approx 7.6$ Hz.

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:Waves

⏱ 2mℹ️ Source: QB

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