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Physics - Sound Wave Question with Solution | TestHub

PhysicsSound Wave302Medium2 minQB

PhysicsMediummultiple choice

The second overtones of an open organ pipe A and a closed pipe B have the same frequency at a given temperature. It follows that the ratio of the :-

Options:(select one or more)

Answer:

C, D

Solution:

Second overtones equal: $\frac{3 v}{2 ℓ _{O}} = \frac{5 v}{4 ℓ _{C}}$ , so $\frac{ℓ _{O}}{ℓ _{C}} = \frac{6}{5}$ and $\frac{ℓ _{B}}{ℓ _{A}} = \frac{5}{6}$ (C)

First overtones: $\frac{n _{A}^{'}}{n _{B}^{'}} = \frac{v / ℓ _{O}}{3 v /4 ℓ _{C}} = \frac{4 ℓ _{C}}{3 ℓ _{O}} = \frac{10}{9}$ (D)

Answers (C, D)

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:302

⏱ 2mℹ️ Source: QB

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