Physics - Sound Wave Question with Solution | TestHub

If point P is fixed so that $\mathrm{AP}:\mathrm{PB}=1:4$, then the smallest frequency for which the sonometer wire resonates is 5 kHz .

If P taken at midpoint of AB and fixed, then, when the wire vibrates in the third harmonic of its fundamental, the number of nodes in the wire (including A and B ) will be totally 10 .

If the fixed point P divides AB in the ratio $1:2$, then the tension needed to make the string vibrate at 1 kHz will be 3 T . (neglecting the terminal effects)

The fundamental frequency of the sonometer wire when P divides AB in the ratio $\mathrm{a}:\mathrm{b}$ will be the same as the fundamental frequency when P divides AB in the ratio $\mathrm{b}:\mathrm{a}$.