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PhysicsSound WaveStanding waveMedium2 minPYQ_2023

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If the end correction of an open pipe is $0.8 cm$ , then the inner radius of that pipe is

Answer:

Solution:

For an open pipe, $e = 0.6 d$ $∴ d = \frac{e}{0.6} ∴ 2 r = \frac{e}{0.6} ∴ r = \frac{0.8}{1.2} = \frac{2}{3} cm$

Stream:MHT_CETSubject:PhysicsTopic:Sound WaveSubtopic:Standing wave

⏱ 2mℹ️ Source: PYQ_2023

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