Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveDopler's effectEasy2 minPYQ_2020

PhysicsEasysingle choice

A sound source emitting sound of frequency $450 Hz$ is approaching a stationary observer with velocity $30 m s^{- 1}$ and another identical source is going away from the observer with the same velocity. If the velocity of sound is $330 m s^{- 1}$ , then the difference of frequencies heard by observer is

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Solution:

$f_{1} = (\frac{v}{v - v_{s}}) f_{0} = \frac{330}{330 - 30} \times 450$

$f_{1} = \frac{330}{300} \times 450 = 11 \times 45$

$f_{1} = 495 H z$

$f_{2} = \frac{330}{360} \times 450$

$f_{2} = 412.5 H z$

$Δ f = 82.5 H z$

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:Dopler's effect

⏱ 2mℹ️ Source: PYQ_2020

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