Physics - Sound Wave Question with Solution | TestHub

The length of closed pipe is denoted using $\mathrm{L}$. Let $l$ be the length of open pipe and $\mathrm{v}$ be the velocity. Frequency of second overtone of an open organ pipe is ${\mathrm{n}}_{\mathrm{o}}=\frac{3\mathrm{v}}{2l}$ Frequency of first overtone of a closed pipe is ${\mathrm{n}}_{\mathrm{c}}=\frac{3\mathrm{v}}{4\mathrm{L}}$ Given: ${\mathrm{n}}_0={\mathrm{n}}_{\mathrm{c}}$ $\frac{3\mathrm{v}}{2l}=\frac{3\mathrm{v}}{4\mathrm{L}}$ $\mathrm{L}=\frac{l}{2}$ $\therefore l=2\mathrm{L}$