Physics - Sound Wave Question with Solution | TestHub

Let $l$ be the length of the pipe and $v$ the speed of the sound. The frequency of the open organ pipe of ${\mathrm{p}}^{\text{th }}$ overtone is, ${\mathrm{f}}_0=(\mathrm{p}+1)\frac{\mathrm{v}}{21}$ And frequency of closed organ pipe of nth overtone is, ${\mathrm{f}}_{\mathrm{c}}=(\mathrm{p}+2)\frac{\mathrm{v}}{41}$ The desired ratio is thus, $\frac{{\mathrm{f}}_0}{{\mathrm{f}}_{\mathrm{c}}}=\frac{2(\mathrm{p}+1)}{2\mathrm{p}+1}$