Frequency of the em signal emitted by a rocket is 4 × 10 7 H z . If apparent frequency observed on earth is 3.2 × 10 7 H z , then velocity with which rocket is moving away is [speed of light = c ]

We know that υ = υ 0 c - v c + v or v = ∆ υ υ 0 × c v = 0.8 × 10 7 4 × 10 7 × 3 × 10 8 = 6 × 10 7 m s - 1 = 0.2 c

Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveDopler's effectMedium2 minPYQ_2020

PhysicsMediumsingle choice

Frequency of the em signal emitted by a rocket is $4 \times 10^{7} H z$ . If apparent frequency observed on earth is $3.2 \times 10^{7} H z$ , then velocity with which rocket is moving away is [speed of light = $c$ ]

Options:

Answer:

Solution:

We know that

$υ = υ_{0} \sqrt{\frac{c - v}{c + v}}$

or $v = \frac{∆ υ}{υ_{0}} \times c$

$v = \frac{0.8 \times 10^{7}}{4 \times 10^{7}} \times 3 \times 10^{8}$

$= 6 \times 10^{7} m s^{- 1} = 0.2 c$

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:Dopler's effect

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...