The length of an open pipe is 48 cm and its fundamental frequency is 320 Hz . If its one end is closed then its fundamental frequency will be

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TestHub · Accepted Answer

For an open pipe, the fundamental frequency $f_{o} = \frac{v}{2 L}$ .

Given $f_{o} = 320$ Hz and $L = 48$ cm.

So, $v = 2 f_{o} L = 2 \times 320 \times 0.48 = 307.2$ m/s.

When one end is closed, the pipe becomes a closed pipe. The fundamental frequency for a closed pipe is $f_{c} = \frac{v}{4 L}$ .

$f_{c} = \frac{307.2}{4 \times 0.48} = \frac{307.2}{1.92} = 160$ Hz.

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