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PhysicsSound WaveMiscellaneousMedium2 minPYQ_2022
PhysicsMediumnumerical

The speed of a transverse wave passing through a string of length50 cmand mass10 gis60 m s-1. The area of cross-section of the wire is2.0 mm2and its Young's modulus is1.2×1011 N m-2. The extension of the wire over its natural length due to its tension will bex×10-5 m. The value ofxis _____ .

Answer:
15.00
Solution:

The wave speed in string is given by vw=Tμ, where, T is tension and μ=ml is linear mass density.

Putting the values, we have

60=T10×10-3×0.5

T=602×10-20.5=72 N

The Young's modulus is given by Y=FlAl, here, A is area.

From above the extension of the wire is Δl=TlAY=72×0.52×10-6×1.2×1011=72×524×10-5=15×10-5 m.

Hence, the value of x=15.

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:Miscellaneous
2mℹ️ Source: PYQ_2022

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