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PhysicsSound WaveStanding waveEasy2 minPYQ_2020

PhysicsEasysingle choice

In a resonance column first and second resonance are obtained at depths $22.7 cm$ and $70.2 cm$ . The third resonance will be obtained at a depth

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Answer:

Solution:

$l_{1} + x = 22.7 + x = \frac{λ}{4}$

$l_{2} + x = 70.2 + x = \frac{3 λ}{4}$

$l_{3} + x = \frac{5 λ}{4}$

$x = \frac{l_{2} - 3 l_{1}}{2} = \frac{70.2 - 68.1}{2} = \frac{2.1}{2} = 1.05 c m$

$\frac{l_{3} + x}{l_{1} + x} = 5$

$l_{3} = 5 l_{1} + 4 x = 5 \times 22.7 + 4 \times 1.05 = 117.7 c m$

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:Standing wave

⏱ 2mℹ️ Source: PYQ_2020

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