Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveStanding waveHard2 minPYQ_2020

PhysicsHardsingle choice

A massless rod of length $l$ is hung from the ceiling with the help of two identical wires attached at its ends. A block is hung on the case, the frequency of the $1^{st}$ harmonic of the wire on the left end is equal to the frequency of the $2^{nd}$ harmonic of the wire on the right. The value of $X$ is

Options:

Answer:

Solution:

$v = λ f$

$\frac{\sqrt{\frac{T_{1}}{μ}}}{\sqrt{\frac{T_{2}}{μ}}} = \frac{2 l f}{l f}$

$\frac{T_{1}}{T_{2}} = 4$

$T_{1} + T_{2} = M g$ ; $T_{2} = \frac{M g}{5}$

$Σ t_{B} = 0 \Rightarrow M g \times X = (\frac{M g}{5}) \times l$ ;

$X = \frac{l}{5}$

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:Standing wave

⏱ 2mℹ️ Source: PYQ_2020

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