Two waves are described by the equations:
$y_{1} = A \cos (0.5 π x - 100 π t)$
And $y_{2} = A \cos (0.46 π x - 92 π t)$
Here $x$ and $y$ are in $m$ and $t$ is in $s$ .
Find the number of times $y_{1} + y_{2}$ becomes zero per second, at $x = 0$ .

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TestHub · Accepted Answer

At x = 0 , y = y 1 + y 2 = 2 A cos ⁡ 96 π t cos ⁡ 4 π t Frequency of cos ⁡ 96 π t = 48 H z and that of cos ⁡ ( 4 π t ) function is 2 Hz In one-second cos function becomes zero at 96 times and second at 4 times. Hence net y will become zero 100 times in 1 second.

Physics - Sound Wave Question with Solution | TestHub

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