Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveBeatsEasy2 minPYQ_2020

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There are two waves having wavelength $100 cm$ and $101 cm$ and same velocity $303 {m s}^{- 1} .$ The beat frequency is

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Solution:

If $f_{1}$ and $f_{2}$ are the frequencies $(f_{1} > f_{2})$ of the two waves, then the beat frequency $f_{b} = f_{1} - f_{2}$

Frequency of $1^{s t}$ wave,

$f_{1} = \frac{V_{1}}{λ_{1}} = \frac{303}{100} \times 10^{2} = 3.03 \times 10^{2} H z$

For $2^{n d}$ wave, $f_{2} = \frac{V_{1}}{λ_{2}} = \frac{303}{101} \times 10^{2} = 3 \times 10^{2} H z$

So, beat frequency $= f_{1} - f_{2}$

$= 3.03 \times 10^{2} - 3 \times 10^{2} = . 03 \times 10^{2} = 3 H z$

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:Beats

⏱ 2mℹ️ Source: PYQ_2020

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