Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveBeatsEasy2 minPYQ_2020

PhysicsEasysingle choice

The frequencies of two sound sources are $256 H z$ and $260 H z$ . At $t = 0$ , the intensity of sound is maximum. Then the phase difference at the time $t = \frac{1}{16} s$ will be

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Answer:

Solution:

The time interval between two consecutive beats

$T = \frac{1}{n_{1} - n_{2}} = \frac{1}{260 - 256} = \frac{1}{4} s$

So, $t = \frac{1}{16} = \frac{T}{4} s$

By using,
time difference $= \frac{T}{2 π} \times$ Phase difference

$\Rightarrow \frac{T}{4} = \frac{T}{2 π} \times ϕ$

$\Rightarrow ϕ = \frac{π}{2}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Sound WaveSubtopic:Beats

⏱ 2mℹ️ Source: PYQ_2020

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