Physics - Sound Wave Question with Solution | TestHub

From the formula for the speed of sound in air

$\frac{v_1}{v_2}=\sqrt{\left(\frac{T_1}{T_2}\right)}$

Or$\frac{v_1}{2v_1}=\sqrt{\left(\frac{273+27}{T_2}\right)}$

Or$\frac{1}{2}=\sqrt{\left(\frac{300}{T_2}\right)}$

Squaring the Eq. (i), we get

$\frac{1}{4}=\frac{300}{T_2}$

Or$T_2=300\times 4=1200 \mathrm{K}$
$= 1200 - 273 = 927 °\mathrm{C}$