Three waves of equal frequency having amplitudes 10 mm , 4 mm , and 7 mm arrive at a given point with a successive phase difference of π 2 , the amplitude of the resulting wave in mm is given by

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TestHub · Accepted Answer

As phase difference between waves of amplitudes $10 m m$ and $7 m m$ is $π$ , therefore, their resultant amplitude $= 10 - 7 = 3 m m$ .
Now amplitudes $3 m m$ and $4 m m$ have a phase difference $= \frac{π}{2}$ .

$∴$ Resultant amplitude $= \sqrt{3^{2} + 4^{2}} = 5 m m$

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