Physics - Sound Wave Question with Solution | TestHub

For a resonance tube, the resonating lengths $l_1$ and $l_2$ with end correction $e$ are given by:

$l_1+e=\frac{\lambda }{4}$

$l_2+e=\frac{3\lambda }{4}$

Given $l_1=15$ cm and $e=1$ cm:

$15+1=\frac{\lambda }{4}$

$\frac{\lambda }{4}=16$ cm

For the next resonating length $l_2$:

$l_2+e=3\left(\frac{\lambda }{4}\right)$

$l_2+1=3\times 16$

$l_2+1=48$

$l_2=47$ cm

Answer: 47 cm