Physics - Sound Wave Question with Solution | TestHub

A source of sound is moving with constant velocity of $30$ mis emitting a note of frequency $256\mathrm{Hz}$. The ratio of frequencies observed by a stationary observer while the source is approaching him and after it crosses him is $6:5$. $V_S=30\mathrm{m}/\mathrm{s}{\mathrm{n}}_0=256\mathrm{Hz}$ $n_1=n_0\frac{V}{V-V_s}$ $n_2=n_0\frac{V}{V+V_s}$ $\therefore \frac{n_1}{n_2}=\frac{V+V_s}{V-V_s}=\frac{360}{300}=\frac{6}{5}$