Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveStanding waveEasy2 minPYQ_2020

PhysicsEasysingle choice

An organ pipe open at one end and closed at other, has a length $L$ . The wavelengths of the three lowest resonating frequencies that can be produced by this pipe are

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Answer:

Solution:

$L = (2 n - 1) \frac{λ}{4}$
$λ = \frac{4 L}{(2 n - 1)}$

Hence,
$λ_{1} = \frac{4 L}{2 (1) - 1} = 4 L$

$λ_{2} = \frac{4 L}{4 - 1} = \frac{4 L}{3}$
$λ_{3} = \frac{4 L}{6 - 1} = \frac{4 L}{5}$

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:Standing wave

⏱ 2mℹ️ Source: PYQ_2020

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