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PhysicsSound WaveMiscellaneousMedium2 minPYQ_2020

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If a transverse pulse is created at the topmost point of a uniform rope suspended vertically, then

Answer:

Solution:

Tension at $P = \frac{m}{L} gx = μgx$

$v_{} = \sqrt{\frac{T}{μ} =} \sqrt{gx}$

$a_{} = \frac{d v}{d t} = \frac{d \sqrt{g x}}{d t}$

$a = \frac{\sqrt{g}}{2 \sqrt{x}} \frac{d x}{d t} = \frac{\sqrt{g}}{2 \sqrt{x}} v = \frac{g}{2}$

Thus with decrease in $x$ , speed of pulse will also decrease but at constant rate.

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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