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Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveWavesMedium2 minQB

PhysicsMediuminteger

A closed pipe of fixed length resonates at $v /4 L$ . If air ( $v = 340$ m/s) is replaced by helium ( $v = 1020$ m/s), by what factor does the fundamental frequency change?

Answer:

Solution:

$f \propto v$ , so the factor is $1020/340 = 3$ .

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:Waves

⏱ 2mℹ️ Source: QB

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