Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveStanding waveMedium2 minPYQ_2020

PhysicsMediumsingle choice

A pipe closed at one end has length $83 cm$ . The number of possible natural oscillations of air column whose frequencies lie below $1000 Hz$ are (velocity of sound in air $= 332 m s^{- 1}$ )

Options:

Answer:

Solution:

Fundamental frequency

$n = \frac{V}{4 L} = \frac{332}{4 \times 83 \times 10^{- 2}} = 100$ .

Hence possible frequencies are $n = 100$ .

$n_{1} = 300$ .

$n_{2} = 500$ .

$n_{3} = 700.$

$n_{5} = 900$ .

Stream:JEESubject:PhysicsTopic:Sound WaveSubtopic:Standing wave

⏱ 2mℹ️ Source: PYQ_2020

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