Physics - Sound Wave Question with Solution | TestHub

$v=n\lambda$

$\therefore \lambda =\frac{v}{n}=\frac{300}{500}=\frac{3}{5} \mathrm{m}$

Now, phase difference

$=\frac{2\pi }{\lambda }\times \text{path difference}$

$\therefore \frac{\pi }{3}=\frac{2\pi }{\lambda }\times \text{path difference}\mathrm{ }$

$\mathrm{o}\mathrm{r}\mathrm{ }\mathrm{ }\mathrm{ }\frac{\mathrm{\pi }}{3}=\frac{2\pi \times 5}{3}\times \text{path difference}$

$\text{path difference}=\frac{3\times 60\times \mathrm{\pi }}{2\pi \times 5\times 180}=0.1 \mathrm{m}$