A bat emitting an ultrasonic wave of frequency 4.5 × 1 0 4 Hz at speed of 6 m / s between two parallel walls. The two frequencies heared by the bat will be

Frequency received by bat after reflection from wall (1). t 2 = f [ v + u v − u ] = 4.5 × 1 0 4 [ 300 + 6 330 − 6 ] = 4.34 × 1 0 4 Hz

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Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveDopler's effectMedium2 minPYQ_2016

PhysicsMediumsingle choice

A bat emitting an ultrasonic wave of frequency $4.5 \times 1 0^{4} Hz$ at speed of $6 m / s$ between two parallel walls. The two frequencies heared by the bat will be

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Frequency received by bat after reflection from wall (1). $t_{2} = f [\frac{v - u}{v + u}] = 4.5 \times 1 0^{4} [\frac{330 - 6}{300 + 6}] = 4.34 \times 1 0^{4} Hz$

Stream:JIPMERSubject:PhysicsTopic:Sound WaveSubtopic:Dopler's effect

⏱ 2mℹ️ Source: PYQ_2016

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