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Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveBeatsEasy2 minPYQ_2020

PhysicsEasysingle choice

A set of $56$ tuning forks are arranged in series of increasing frequencies. If each fork gives $4$ beats with preceding one and the frequency of the last is twice than that of first, then frequency of the first fork is

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Answer:

Solution:

$n_{56} = n_{1} + (56 - 1) 4$

Also, $n_{56} = 2 n_{1}$

$∴ 2 n_{1} = n_{1} + 55 \times 4$

$∴ n_{1} = 220 Hz$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Sound WaveSubtopic:Beats

⏱ 2mℹ️ Source: PYQ_2020

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