Physics - Sound Wave Question with Solution | TestHub

$\frac{F_1}{F_2}=2$, Speed of approach = Speed of leaving
The apparent frequency of sound observed by observer when it is approaching source is given by
$F_1=\frac{V+V_1}{V}.f_0$....(i)
When observer is moving away from source
$F_2=\frac{V-V_1}{V}{f}_0$....... (ii)
Here$f_0$is the frequency of sound wave
Taking ratio of (i) with (ii) we have
$\frac{F_1}{F_2}=\frac{V}{V-V_1}\times \frac{V+V_1}{V}=\frac{V+V_1}{V-V_1}$
$\therefore 2=\frac{V+V_1}{V-V_1}$
$\therefore 2V-2V_1=V+V_1$
$\therefore 2V-V=3V_1$
$\therefore \frac{V}{V_1}=3$