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Physics - Sound Wave Question with Solution | TestHub

PhysicsSound WaveStanding waveEasy2 minPYQ_2013

PhysicsEasysingle choice

The fundamental frequency of a closed pipe is equal to the frequency of the second harmonic of an open pipe. The ratio of their lengths is

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Solution:

Let the length of closed pipe is $L_{1}$ and that of pipe is $L_{2}$ . Fundamental frequency of closed pipe, $v_{1} = \frac{v}{4 L _{1}}$ and frequency of second harmonic of open pipe. $v_{2} = 2 \times \frac{v}{2 L _{2}}$ Given, $v_{1} = v_{2}$ $i, θ$ $\frac{v}{4 L _{1}} = \frac{2 v}{2 L _{2}} \Rightarrow \frac{L _{1}}{L _{2}} = \frac{1}{4}$

Stream:WBJEESubject:PhysicsTopic:Sound WaveSubtopic:Standing wave

⏱ 2mℹ️ Source: PYQ_2013

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