Physics - Sound Wave Question with Solution | TestHub

$$\text{ According to the question }$$
Speed of listener $V_L=1{\mathrm{ms}}^{-1}$ Speed of sound $V=330{\mathrm{ms}}^{-1}$ Frequency of each source $v=600\mathrm{Hz}$ $\therefore$ Apparent frequency due to $\mathrm{P}={\mathrm{V}}^{\prime }$ $=\frac{v\left(\mathrm{V}-{\mathrm{V}}_{\mathrm{L}}\right)}{\mathrm{V}}$ Apparent frequency due to $\mathrm{Q}={\mathrm{V}}^{\prime \prime }=$ $\frac{v\left(\mathrm{V}-{\mathrm{V}}_{\mathrm{L}}\right)}{\mathrm{V}}$ $\therefore$ No. of heat heard by the listener per second. $$\begin{array}{rl}& {\mathrm{V}}^{\prime \prime }-{\mathrm{V}}^{\prime }=\frac{v\left(\mathrm{V}-{\mathrm{V}}_{\mathrm{L}}\right)}{\mathrm{V}}-\frac{v\left({\mathrm{V}}_0-{\mathrm{V}}_{\mathrm{L}}\right)}{\mathrm{V}}\\ & =\frac{2v_{\mathrm{L}}}{v}=\frac{2\times 660\times 1}{330}=4\end{array}$$