Physics - Sound Wave Question with Solution | TestHub

Frequency of closed pipe, $n_1=\frac{v}{4l_1}\Rightarrow l_1=\frac{v}{4n_1}$ Frequency of open pipe, $n_2=\frac{v}{2l_1}\Rightarrow l_2=\frac{v}{2n_2}$ when both pipe are joined then length of closed pipe $$\begin{array}{c}l=l_1+l_2\\ \frac{v}{4n}=\frac{v}{4n_1}+\frac{v}{2n_2}\end{array}$$ or $\frac{1}{2n}=\frac{1}{2n_1}+\frac{1}{n_2}$ or $$\frac{1}{2n}=\frac{n_2+2n_1}{2n_1{n}_2}$$ or $$n=\frac{n_1{n}_2}{n_2+2n_1}$$