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PhysicsSHMCalculation of time periodEasy2 minQB
PhysicsEasysingle choice

A cylindrical piston of massMslides smoothly inside a long cylinder closed at one end, enclosing a certain mass of gas. The cylinder is kept with its axis horizontal. If the piston is disturbed from its equilibrium position, it oscillates simple harmonically. The period of oscillation will be (Assume isothermal process)

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Answer:
A
Solution:

Let the piston be displaced through distance x towards left, then volume decreases, pressure increases. If ΔP is an increase in pressure and ΔV is a decrease in volume, then considering the process to take place slowly (i.e. Isothermal)

P1V1=P2V2⇒PV=(P+ΔP)(V-ΔV)
⇒PV=PV+ΔPV-PΔV-ΔPΔV
⇒ΔP.V-P.ΔV=0   (neglecting ΔP.ΔV)
ΔP(Ah)=P(Ax)⇒ΔP=P⋅xh

F=-PAhx

ω=PAMh

T=2πMhPA

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Calculation of time period
⏱ 2mℹ️ Source: QB

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