Physics - SHM Question with Solution | TestHub

For SHM, $v^2={\omega }^2\left(A^2-x^2\right)$: read $v_{\max }$ and A from the graph.

$\omega =\frac{v_{\max }}{A},T=\frac{2\pi }{\omega }$

Substituting the graph values gives option A.

Answer: A