Start Free Mock LoginAlready registered? Login here

Physics - SHM Question with Solution | TestHub

PhysicsSHMCalculation of time periodEasy2 minQB

PhysicsEasysingle choice

Time period of a spring-mass system is $T$ . If this spring is cut into two parts whose lengths are in the ratio 1:3 and the same mass is attached to the longer part, the new time period will be

Options:

Answer:

Solution:

$T = 2 π \sqrt{\frac{m}{k}}$

When spring is cut in the ratio 1 : 3, the force constant of the longer part is $\frac{4 k}{3}$ .

$∴ T' = 2 π \sqrt{\frac{3 m}{4 k}} = \frac{\sqrt{3}}{2} T$

Stream:JEESubject:PhysicsTopic:SHMSubtopic:Calculation of time period

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...